2x^2+7x-555=0

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Solution for 2x^2+7x-555=0 equation:



2x^2+7x-555=0
a = 2; b = 7; c = -555;
Δ = b2-4ac
Δ = 72-4·2·(-555)
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4489}=67$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-67}{2*2}=\frac{-74}{4} =-18+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+67}{2*2}=\frac{60}{4} =15 $

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